Complex phrase also has an inorder flag that I think you're looking for here.

Best,
Erick

On Mon, Jun 12, 2017 at 7:16 AM, Erik Hatcher <erik.hatc...@gmail.com> wrote:
> Understood.   If you need ordered, “sloppy” (some distance) phrases, you 
> could OR in a {!complexphrase} query.
>
> https://cwiki.apache.org/confluence/display/solr/Other+Parsers#OtherParsers-ComplexPhraseQueryParser
>  
> <https://cwiki.apache.org/confluence/display/solr/Other+Parsers#OtherParsers-ComplexPhraseQueryParser>
>
> Something like:
>
>     q=({!edismax … ps=0 v=$qq}) OR {!complexphrase df=nameSearch v=$qq}
>
> where &qq=12345 masitha
>
>         Erik
>
>
>> On Jun 12, 2017, at 9:57 AM, Aman Deep Singh <amandeep.coo...@gmail.com> 
>> wrote:
>>
>> Yes Erik I can use ps=0 but, my problem is that I want phrase which have
>> same sequence and they can be present with in some distance
>> E.g.
>> If I have document masitha xyz 12345
>> I want that to be boosted since the sequence is in order .That's why I have
>> use ps=5
>> Thanks,
>> Aman Deep Singh
>>
>> On 12-Jun-2017 5:44 PM, "Erik Hatcher" <erik.hatc...@gmail.com> wrote:
>>
>> Using ps=5 causes the phrase matching to be unordered matching.   You’ll
>> have to set ps=0, if using edismax, to get exact order phrase matches.
>>
>>        Erik
>>
>>
>>> On Jun 12, 2017, at 1:09 AM, Aman Deep Singh <amandeep.coo...@gmail.com>
>> wrote:
>>>
>>> Hi,
>>> I'm using a phrase query ,but it was applying the phrase boost to the
>> query
>>> where terms are in reverse order also ,which i don't want.Is their any way
>>> to avoid the phrase boost for reverse order and apply boost only in case
>> of
>>> terms are in same sequence
>>>
>>> Solr version 6.5.1
>>>
>>> e.g.
>>> http://localhost:8983/solr/l4_collection/select?debugQuery=o
>> n&defType=edismax&fl=score,nameSearch&indent=on&mm=100%25&
>> pf=nameSearch&q=12345%20masitha&qf=nameSearch&wt=xml&ps=5
>>>
>>>
>>> while my document has value
>>>
>>> in the debug query it is applying boost as
>>> 23.28365 = sum of:
>>> 15.112219 = sum of:
>>> 9.669338 = weight(nameSearch:12345 in 0) [SchemaSimilarity], result of:
>>> 9.669338 = score(doc=0,freq=1.0 = termFreq=1.0
>>> ), product of:
>>> 7.6397386 = idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq
>>> + 0.5)) from:
>>> 2.0 = docFreq
>>> 5197.0 = docCount
>>> 1.2656635 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 - b +
>> b
>>> * fieldLength / avgFieldLength)) from:
>>> 1.0 = termFreq=1.0
>>> 1.2 = parameter k1
>>> 0.75 = parameter b
>>> 5.2576485 = avgFieldLength
>>> 2.56 = fieldLength
>>> 5.44288 = weight(nameSearch:masitha in 0) [SchemaSimilarity], result of:
>>> 5.44288 = score(doc=0,freq=1.0 = termFreq=1.0
>>> ), product of:
>>> 4.3004165 = idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq
>>> + 0.5)) from:
>>> 70.0 = docFreq
>>> 5197.0 = docCount
>>> 1.2656635 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 - b +
>> b
>>> * fieldLength / avgFieldLength)) from:
>>> 1.0 = termFreq=1.0
>>> 1.2 = parameter k1
>>> 0.75 = parameter b
>>> 5.2576485 = avgFieldLength
>>> 2.56 = fieldLength
>>> 8.171431 = weight(*nameSearch:"12345 masitha"~5 *in 0) [SchemaSimilarity],
>>> result of:
>>> 8.171431 = score(doc=0,freq=0.33333334 = phraseFreq=0.33333334
>>> ), product of:
>>> 11.940155 = idf(), sum of:
>>> 7.6397386 = idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq
>>> + 0.5)) from:
>>> 2.0 = docFreq
>>> 5197.0 = docCount
>>> 4.3004165 = idf, computed as log(1 + (docCount - docFreq + 0.5) / (docFreq
>>> + 0.5)) from:
>>> 70.0 = docFreq
>>> 5197.0 = docCount
>>> 0.6843655 = tfNorm, computed as (freq * (k1 + 1)) / (freq + k1 * (1 - b +
>> b
>>> * fieldLength / avgFieldLength)) from:
>>> 0.33333334 = phraseFreq=0.33333334
>>> 1.2 = parameter k1
>>> 0.75 = parameter b
>>> 5.2576485 = avgFieldLength
>>> 2.56 = fieldLength
>>>
>>> Thanks,
>>> Aman Deep Singh
>

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