HI Otis, The debug information as following, seems there is no "product() process" .
<lst name="debug"> <str name="rawquerystring">_l_all:"測試"</str> <str name="querystring">_l_all:"測試"</str> <str name="parsedquery">PhraseQuery(_l_all:"測 試")</str> <str name="parsedquery_toString">_l_all:"測 試"</str> <lst name="explain"> <str name="222"> 41.11747 = (MATCH) weight(_l_all:"測 試" in 0) [DefaultSimilarity], result of: 41.11747 = fieldWeight in 0, product of: 4.1231055 = tf(freq=17.0), with freq of: 17.0 = phraseFreq=17.0 1.4246359 = idf(), sum of: 0.71231794 = idf(docFreq=3, maxDocs=3) 0.71231794 = idf(docFreq=3, maxDocs=3) 7.0 = fieldNorm(doc=0) </str> <str name="223"> 14.246359 = (MATCH) weight(_l_all:"測 試" in 0) [DefaultSimilarity], result of: 14.246359 = fieldWeight in 0, product of: 1.0 = tf(freq=1.0), with freq of: 1.0 = phraseFreq=1.0 1.4246359 = idf(), sum of: 0.71231794 = idf(docFreq=3, maxDocs=3) 0.71231794 = idf(docFreq=3, maxDocs=3) 10.0 = fieldNorm(doc=0) </str> <str name="211"> 10.073696 = (MATCH) weight(_l_all:"測 試" in 0) [DefaultSimilarity], result of: 10.073696 = fieldWeight in 0, product of: 1.4142135 = tf(freq=2.0), with freq of: 2.0 = phraseFreq=2.0 1.4246359 = idf(), sum of: 0.71231794 = idf(docFreq=3, maxDocs=3) 0.71231794 = idf(docFreq=3, maxDocs=3) 5.0 = fieldNorm(doc=0) </str> </lst> <str name="QParser">LuceneQParser</str> <lst name="timing"> <double name="time">6.0</double> <lst name="prepare"> <double name="time">0.0</double> <lst name="org.apache.solr.handler.component.QueryComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.FacetComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.MoreLikeThisComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.HighlightComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.StatsComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.DebugComponent"> <double name="time">0.0</double> </lst> </lst> <lst name="process"> <double name="time">6.0</double> <lst name="org.apache.solr.handler.component.QueryComponent"> <double name="time">3.0</double> </lst> <lst name="org.apache.solr.handler.component.FacetComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.MoreLikeThisComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.HighlightComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.StatsComponent"> <double name="time">0.0</double> </lst> <lst name="org.apache.solr.handler.component.DebugComponent"> <double name="time">3.0</double> </lst> </lst> </lst> </lst> 2012/11/20 Otis Gospodnetic <otis.gospodne...@gmail.com> > Hi Floyd, > > Use &debugQuery=true and let's see it.:) > > Otis > -- > Performance Monitoring - http://sematext.com/spm/index.html > Search Analytics - http://sematext.com/search-analytics/index.html > > > > > On Mon, Nov 19, 2012 at 9:29 PM, Floyd Wu <floyd...@gmail.com> wrote: > > > Hi there, > > > > Before ExternalFielField introduced, change document boost value to > achieve > > custom ranking. My client app will update each boost value for documents > > daily and seem to worked fine. > > Actual ranking could be predicted based on boost value. (value is > > calculated based on click, recency, and rating ). > > > > I'm now try to use ExternalFileField to do some ranking, after some > test, I > > did not get my expectation. > > > > I'm doing a sort like this > > > > sort=product(score,abs(rankingField))+desc > > But the query result ranking won't change anyway. > > > > The external file as following > > doc1=3 > > doc2=5 > > doc3=9 > > > > The original score get from Solr result as fllowing > > doc1=41.042 > > doc2=10.1256 > > doc3=8.2135 > > > > Expected ranking > > doc1 > > doc3 > > doc2 > > > > What wrong in my test, please kindly help on this. > > > > Floyd > > >
