Simple math: x times zero equals zero.
That's why the default document boost is 1.0 - score times 1.0 equals score.
Any particular reason you wanted to zero out the document score from the
document level?
-- Jack Krupansky
-----Original Message-----
From: Tony Mullins
Sent: Tuesday, July 09, 2013 9:23 AM
To: solr-user@lucene.apache.org
Subject: Re: Calculating Solr document score by ignoring the field.
I am passing boost value (via nutch) and i.e boost =0.0.
But my question is why Solr is showing me score = 0.0 when my boost (index
time boost) = 0.0 ?
Should not Solr calculate its documents score on the basis of TF-IDF ? And
if not how can I make Solr to only consider TF-IDF while calculating
document's score ?
Regards,
Khan
On Tue, Jul 9, 2013 at 4:46 PM, Erick Erickson
<erickerick...@gmail.com>wrote:
My guess is that you're not really passing on the boost field's value
and getting the default. Don't quite know how I'd track that down
though....
Best
Erick
On Tue, Jul 9, 2013 at 4:09 AM, imran khan <imrankhan.x...@gmail.com>
wrote:
> Greetings,
>
> I am using nutch 2.x as my datasource for Solr 4.3.0. And nutch passes
> on
> its own <boost> field to my Solr schema
>
> <field name="boost" type="float" stored="true" indexed="false"/>
>
> Now due to some reason I always get <boost> = 0.0 and due to this my
Solr's
> document score is also always 0.0.
>
> Is there any way in Solr that it ignores the <boost> field's value for
its
> document's score calculation ?
>
> Regards,
> Khan
