>From a previous discussion (xpress output, the example is shown below)
I learned that the xpress value in proteinprophet is calculated using
the equation:
average ratio = 10^(mean(log(x))
Now, I am wondering how the standard deviation ( +- 0.15 in the
example below) is calculated.
Thomas
XPRESS ratio in ProteinProphet: light:heavy (0.61 ± 0.15)
# log10(#)
0.22 -0.6575
0.93 -0.0315
0.51 -0.2924
0.84 -0.0757
1.01 0.0043
sum(log10)/5 = -0.2105
10^(-0.2105) = 0.6157
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