Oh, btw, the probabilities I posted were wrong...I forgot to consider that each corner can be on 8 positions (one at a time, of course). So, the correct is: (from Richard Carr's BCFTSS) 0 corners to orient (8 correct) -> 1/2187 (about 0,046%) 2 corners to orient (6 correct) -> 56/2187 (about 2,6%) 3 corners to orient (5 correct) -> 112/2187 (about 5%) 4 corners to orient (you know) -> 420/2187 (about 19,2%) 5 corners to orient ( ... ) -> 560/2187 (about 25,6%) 6 corners to orient ( ... ) -> 616/2187 (about 28,2%) 7 corners to orient ( ... ) -> 336/2187 (about 15,4%) 8 corners to orient ( ... ) -> 86/2187 (about 4%)
Well, 2,6% is a low probability, but is just for CO, and what this means on the entire solve I don't know... Pedro Pedro <[EMAIL PROTECTED]> escreveu: Yeah, you're right...hehe...you just can't have 1 corner incorrectly oriented. Well, I usually have 4-6 corners to twist.... I'm getting confused...hehe But, like I said, and for the people who use Stefan's method? What's a lucky case? Pedro Bob Burton <[EMAIL PROTECTED]> escreveu: You can't have 3 corners incorrectly oriented? R U R' U R U2 R' ? Right? What I meant about the proportion is that for example, if the average number of twisted corners is 6 (which it should be), and you only have to twist two of them, if you normally do two at a time, then you are saving 67% of your CO step for execution, and then saving an additional amount of time by memorizing less. I don't use that BLD method, though, so I'm not sure if this is right. This is based on what I THINK I know. :) ~ Bob --- In [email protected], Pedro <[EMAIL PROTECTED]> wrote: > > Well, I'm not a probabilites expert, but let's try... > > You can't have just 1 or 3 or 5 or 7 corners correctly (or incorrectly) oriented. Always even numbers. So, assuming that the probability of one corner being oriented is 1/3, you have 1/9 of probability of having 2 correct corners. The probability of having 4 correct ones is 1/81. For 6 correct corners is 1/729. And for all 8 corners correct is 1/6561. So, the probability of having a case like I had is 1/729. > I don't know what proportion of the solve it saved. People solve the cube BLD differently. I use commutators for solving the CO. Really don't know the proportion...: ( > > Pedro > > Bob Burton <[EMAIL PROTECTED]> escreveu: > I would say that depends on what the probability of you having a case > as lucky as this is, and also what proportion of your solution it > saves. Do you know this information? > > --- In [email protected], "pedrosino1" > <[EMAIL PROTECTED]> wrote: > > > > I'm speaking specifically about BLD solving, but... > > > > Yesterday I broke my PB for BLD solving. I scrambled with NetCube, > > memorised, solved, and looked at the time: 2:24.08. Well, I was pretty > > happy with that. But, during my solve, I had just 2 corners wrongly > > oriented. So, technically, it's a lucky case. But I was thinking: > > I can be lucky on a competition...or not? If Oficcial World Records can > > contain lucky cases, why not UWR can list them? Of course there are > > cases that are *very* lucky, like skipping OLL or PLL, or having no > > corners or no edges to orient (on BLD). But there are cases that are > > just a bit lucky. So, why not listing them? And another thing: how is a > > case defined as lucky to someone who uses Stefan's method? > > > > Well, just my humble opinion, but... > > > > Pedro > > > > > > > > > SPONSORED LINKS > Jigsaw puzzle game Free puzzle inlay games Educational game and puzzle Word puzzle game Kid puzzle game Puzzle games > > --------------------------------- > YAHOO! GROUPS LINKS > > > Visit your group "speedsolvingrubikscube" on the web. > > To unsubscribe from this group, send an email to: > [EMAIL PROTECTED] > > Your use of Yahoo! Groups is subject to the Yahoo! Terms of Service. > > > --------------------------------- > > > > > > > --------------------------------- > Yahoo! doce lar. Faça do Yahoo! sua homepage. > > [Non-text portions of this message have been removed] > --------------------------------- YAHOO! GROUPS LINKS Visit your group "speedsolvingrubikscube" on the web. To unsubscribe from this group, send an email to: [EMAIL PROTECTED] Your use of Yahoo! Groups is subject to the Yahoo! 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