Hello Everyone.
PELLs I Use
R2 U (RUR'U')R'U'(R'UR') 11
R2 d'(M'U2M) d'r2 7
M2 U M2 U2 M2 U M2 7
M2 U M2 U u2 M' E2 M' 8
>From Speedcubing.com, I read this in the Algorithms section
"- in 1 out of 12 cases you can solve the LL in one algorithm!
- in 8 out of 12 cases you leave an easy 3-cycle of edges
- in 2 out of 12 cases you leave the edges zigzag permutation
- in 1 out of 12 cases you leave the edges cross permutation"
So PELL Avg = (1(0) + 4(11) + 4(7) + 2(8) + 1(7))/12
= (44 + 28 + 16 + 7)/12
= 95/12
= 7.916666
Is this correct?
ELL Move Count 12?
PELL Move Count 8?
CLL Move Count 9?
COLL Move Count 14?
I wanted to again ask about these categories. The Only ones I know
for sure are PELL = 8 and Step 4 = 13.2, because I calculated myself.
Bob, you gave me 9 and 14 for CLL/COLL, I think.
Has anybody calculated CLL, COLL, OLL, PLL, ELL, PELL, but taking into
account the chance or occurance of each case? Have I done that
correctly with PELL?
Jason Kovacic
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