All right, like, last year in the Caltech groups, there was a long and 
tedious discussion with David Saliva.  Go online and look up the "Monty 
Hall Problem".  The answer is 2/3, 1/3.  If you don't believe me, try 
playing the game.

Tyson Mao
MSC #631
California Institute of Technology

On Dec 24, 2005, at 9:06 PM, pjgat09 wrote:

> I would think this:
> You have a 1/3 chance of being right
> Host opens empty door
> Now lets assume that door has gone away. There are only 2 doors, and
> you chose one. You still have a 1/2 chnace no matter what the host
> does. Opening a door didnt change your chances.
>
> Peter Greenwood
>
> --- In [email protected], Chris Hunt
> <[EMAIL PROTECTED]> wrote:
>>
>> Ah, sounds like my explanation might be wrong, but at least I pick
> the right
>> door :)
>>
>> -Chris
>>
>> On 12/24/05, Evan Gates <[EMAIL PROTECTED]> wrote:
>>>
>>> After you choose a door, the host has to open one.  Two out of the
> three
>>> times, he has no choice which one to open.  When you pick the door at
>>> first,
>>> you have a 1/3 chance of being right.  After he opens a door, if
> you stay
>>> with the door you first chose, you still have a 1/3 chance, if you
> switch,
>>> you have a 2/3 chance.  There are three possibilities, considering 
>>> you
>>> switch doors.
>>> 1) you were right at first, and you lose
>>> 2) you were wrong at first, and you win
>>> 3) you were wrong at first(other door), and you win
>>> Two out of the three possible outcomes, you win
>>>
>>> It also might help if you think of 100 doors instead of 3.
>>> You choose one door, you have a 1/100 or 1% chance of being right.
>  You
>>> stay
>>> with that door while the host opens 98 doors, so you are down to
> 2, the
>>> one
>>> you originally chose, and the last one that he hasn't open.
> Staying with
>>> your first choice, you still have a 1% chance.  But if you switch, 
>>> you
>>> have
>>> a 99% chance.  There is a reason that he hasn't yet opened that
> door.  By
>>> opening the other ones, he's giving you a clue about where the car 
>>> is.
>>>
>>> and boy do I hope I'm right, because rereading that i sound really
>>> arrogant lol (really, I'm not and I don't mean to be) ;-)
>>> -Evan
>>>
>>> Until next time, Happy Cubing
>>> http://www.deepcube.net
>>>
>>>
>>> On 12/24/05, pjgat09 <[EMAIL PROTECTED]> wrote:
>>>>
>>>> Hmm, lets see. You start with 3 doors, one with a car. The host
>>>> cancels out a door giving you 2 doors. That means your guess has
> a 1/2
>>>> chance of being correct. There is no point in changing, its 50-50 no
>>>> matter what. (unless the game is rigged where the car moves from one
>>>> door to the next :P )
>>>>
>>>> I would stay with my first choice, though it doesnt matter. Its all
>>>> personal preferance.
>>>>
>>>> Peter Greenwood
>>>>
>>>> --- In [email protected], Pedro
> <[EMAIL PROTECTED]>
>>>> wrote:
>>>>>
>>>>> Ok, this is off topic, but is interesting...
>>>>>
>>>>>   (please forgive if I make some mistake on the english...)
>>>>>   Suppose you are at a TV show, where you have 3 doors. 1 of the
>>>> doors has a car, and the other 2 don't have anything. So, the show
>>>> presenter asks you to choose a door. So, you choose, but he doesn't
>>>> open your choosen door. He opens an empty door. Then, he makes a
>>>> question: do you want to continue with your first choice or
> change to
>>>> the other door?
>>>>>
>>>>>   What do you do?
>>>>>   What situation gives you more chances of winning?
>>>>>
>>>>>   Think about it...
>>>>>
>>>>>   Pedro
>>>>>
>>>>>
>>>>> ---------------------------------
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>>>>>
>>>>
>>>>
>>>>
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