Thanks, that works! --- In [email protected], Gilles van den Peereboom <[EMAIL PROTECTED]> wrote: > > Oh I'm sorry, the alg is (Rr U2) * 5 > This one is correct ;-) > > This version of the alg is for speedsolving, if you want a purer > version so that it doesn't mess the corners), do (r U2) *5 (r is the 2 > layer counting from the right). > > Good luck ! > Gilles. > > 2005/12/29, christopher_pelley <[EMAIL PROTECTED]>: > > I just tried this (Rr U) * 5, and it doesn't seem to work. Are you > > sure that's the algorithm? I know (R2 u) * 5 moves four edges > > around the equator, but (Rr U) * 5 just produces a scramble for me! > > > > Chris > > > > > > --- In [email protected], Gilles van den > > Peereboom <[EMAIL PROTECTED]> wrote: > > > > > > Try (Rr U) *5 with your two unsolved edges in UF and UB (place the > > two > > > solved pieces (edge center and edge wing) on the right for both of > > > them). Then you'll have 3 edges that can be easily solved. > > > > > > Good luck ! > > > Gilles. > > > > > > 2005/12/27, cube_padiwan <[EMAIL PROTECTED]>: > > > > Hello everyone! I've tried but have been unable to find an > > algorithm or > > > > tutorial for matching the three pieces of the last two edges of a > > > > Professor (5x5x5) Cube. I'm trying to solve the Professor cube > > by using > > > > the method where you solve the centers first, then match all the > > edge > > > > pieces together, which turns the Cube into a 3x3x3. I can get > > all the > > > > edge pieces matched together except for the pieces of the last > > two > > > > edges! This is very aggravating! If anyone knows how to do this > > or has > > > > a link to a site whcih explains this, your help would be very > > much > > > > appreciated! > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > Yahoo! Groups Links > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > > Yahoo! Groups Links > > > > > > > > > > > > > > >
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