My second post, and inside 10 minutes...
I recently got a 5x5 cube, and at the moment, can solve it
everytime, but I feel my method isn't 'tight' and elegant enough.
Basically, and as is pretty inuitive, I complete the centers, build
the edge triplets and solve as a 3x3, which requires minimal thought
(and practically 0 extra algs). The 'center solution' is naturally
slow, so I'm going talk exclusively about associating the edge
triplets. I'd like to hear from anyone who has a relatively
EFFICIENT way of avoiding the 'parity' error (or, more correctly,
when you must swap TWO small edge cubies, instead of three). To
correct this, I simply perform RrU2 five times, which muddles up a
few edges, but yields a cycle of three. This, I find, is incredibly
inelegant. Are there any ways to COMPLETELY avoid this possibility.
I initially thought looking ahead when I had four edges to go
(to 'combine') but this does not seem to have any effect.
So what do you think??
Jon
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