--- In [email protected], "Stefan Pochmann" 
<[EMAIL PROTECTED]> wrote:
> 
> Please try on 3x3 and translate to 5x5 (hope you get the idea):
> U' 2*(R2' U' r2 U F2) U

I just realized the inner part might be interesting for some 
orient-first 3x3 blindcubers:

2 * (R2' U' r2 U F2)

And of course also its various variations, e.g.

2 * (F2 R2' U' r2 U)
2 * (U F2 R2' U' r2)
2 * (L2 U l2 U' F2)

Cheers!
Stefan






 
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