--- In [email protected], "Stefan Pochmann"
<[EMAIL PROTECTED]> wrote:
>
> Please try on 3x3 and translate to 5x5 (hope you get the idea):
> U' 2*(R2' U' r2 U F2) U
I just realized the inner part might be interesting for some
orient-first 3x3 blindcubers:
2 * (R2' U' r2 U F2)
And of course also its various variations, e.g.
2 * (F2 R2' U' r2 U)
2 * (U F2 R2' U' r2)
2 * (L2 U l2 U' F2)
Cheers!
Stefan
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