Shazbot!
2g=64.4
(62.4 is the weight in pounds of a cubic foot of water).
On Feb 17, 2017 5:05 PM, "Brad Casterline" <[email protected]> wrote:

> Vince,
>
> I think you are looking for something with a little more meat on its bones
> than rearranging Q=K*SQRT(P). A few years ago you mentioned K Value.
> Counselor Greenman presented this evidence:
>
> http://www.metropumps.com/ResourcesFrictionLossData.pdf
>
> The first item is Angle Valve, which might be close enough to Hose Valve,
> but the problem is the second item is also Angle Valve with a different
> value and I saw no clarification of what's what with that. But when Steve L
> testified to 3-5 psi loss at 250 gpm I rearanged and I think the second one
> is correct; K Value=2.7- - -
>
> Using the 5 psi loss, hf=11.55 ft.
> I converted 250 gpm to .557 ft^3/sec and 2.5" nominal to .034 ft^2 and
> dividing the first by the second got v= 16.38 ft/sec, squared that, divided
> by 2g (62.4), and then divided 11.55 by that for K Value = 2.77.
> This should be more useful for you because friction head is directly
> proportional to the square of the velocity, and K Value is a counter part
> of Coefficient of Discharge in that C of D = the ideal world based on
> nominal / the reality of the measurement.
>
> still yours after forty years, your first grasshopper,
>
> Brad
> On Feb 17, 2017 8:28 AM, "Vince Sabolik" <[email protected]> wrote:
>
>> Good morning, everyone...
>>
>> Does anybody have a decent K Factor for a 2½" hose valve?
>>
>> Thanks!      Vince
>>
>> 11351 Pearl Road /  Suite 101
>> Strongsville, Ohio 44136
>> Phone 440 238-4800 <(440)%20238-4800> Fax 440 238-4876 <(440)%20238-4876> 
>> Cell
>> 440 724-7601 <(440)%20724-7601>
>>
>>
>> * Vince Sabolik *
>>
>> _______________________________________________
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>>
>>
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