Because Vince asked is the only 'why' I needed, but then I fully understand
he is not everyone's first mentor.
He said he was doing the calcs by hand--- might be some kind of supply type
analysis.

Brad
On Feb 20, 2017 4:48 PM, "Travis Mack, SET" <[email protected]> wrote:

> The question still remains as to "why" something like this would be
> needed.  If it just to plug into a computer to make it run calcs, then use
> Q = k*sqrt(P).
>
> Travis Mack, SET
> MFP Design, LLC
> 2508 E Lodgepole Drive
> Gilbert, AZ 85298480-505-9271 <(480)%20505-9271>
> fax: 866-430-6107 <(866)%20430-6107>email:[email protected]
> http://www.mfpdesign.comhttps://www.facebook.com/pages/MFP-Design-LLC/92218417692
> Send large files to us via: https://www.hightail.com/u/MFPDesign
> LinkedIn: https://www.linkedin.com/in/travismack
>
> On 2/20/2017 3:37 PM, Brad Casterline wrote:
>
> Nice Allan!
>
> And Steve, if you want 1139 at 100 out the valve you are going to need 143
> at the standpipe, to get through the nipple and tee. It's like a sprinkler
> on a sprig calc, only the sprinkler is great big and the sprig is short and
> fat.
>
> Brad
> On Feb 19, 2017 6:01 PM, "AKS-Gmail-IMAP" <[email protected]> wrote:
>
>> Lets look at what FM Global has to say. According to FM Global’s minimum
>> approval standards for these valves, "*Approval Standard for **Angle and
>> Straightaway Hose Valves, **Class Number 1521/1522 , December 2014”*
>>
>> "4.11
>>
>> Friction Loss Test – Traditional Hose Valves Only
>>
>>    1.
>>
>>    4.11.1  Requirement
>>
>>    The valve shall be designed so that the obstruction in the waterway
>>    is minimal. For valves found to be non- compliant with Sections 3.2.3
>>    and/or 3.2.4, friction loss testing is necessary. The valve will be tested
>>    in the full open position, and the friction loss through the valve will be
>>    measured at a flow rate that produces a fluid velocity of 20 ft/sec (6.1
>>    m/sec) in Schedule 40 steel pipe of the same nominal diameter as the 
>> valve.
>>    The measured friction loss shall be less than 10 psi (69 kPa)."
>>
>> The “sections 3.2.3 and/or 3.2.4” in the text refers to physical seat
>> lift dimensions in the valve. So FM does not took at pressure loss if the
>> valve guts meet their internal dimension numbers. The standard does not
>> refer to angle versus straight in regard to pressure loss. Both patterns
>> must meet the same standard. I believe that 20 ft/sec in 2.5” schd. 40 pipe
>> comes to 298 GPM at 10 psi drop, which comes to a K near 94. Figuring FM
>> approval is “better than your average bear.”, you might not want to use a K
>> larger than 94. That 94 K would lose about 7 psi at 250 gpm.
>>
>> Allan Seidel
>> St. Louis, MO
>>
>>
>> On Feb 19, 2017, at 12:44 PM, Brad Casterline <[email protected]>
>> wrote:
>>
>> Of course!
>> I know this is unorthodox thinking, especially for an NFPA 14 maestro.
>> But I figured out quite a few years ago how to get not only K, but the Q
>> and P that goes with it for a flowing outlet with only two pieces of
>> information; the nominal diameter and the coefficient of discharge.
>> And after the twists and turns and showing off and stepping in it this
>> weekend I wanted to take my best shot at being the anybody with a decent K
>> for a 2.5 inch hose valve, as Vince asked.
>> So "In the same way as a nominal 1/2" sprinkler..."
>> K=113.85, if the C of D is .61,
>> final answer.
>>
>> Thanks for hollering back, I was getting lonely out here,
>>
>> Brad
>> On Feb 19, 2017 11:13 AM, "Steve Leyton" <[email protected]>
>> wrote:
>>
>>> Of course, that should have been GPM and not PSI.
>>>
>>>
>>> Steve
>>>
>>>
>>> -------- Original message --------
>>> From: Steve Leyton <[email protected]>
>>> Date: 2/19/17 8:44 AM (GMT-08:00)
>>> To: [email protected], Vince Sabolik <
>>> [email protected]>
>>> Subject: RE: K for a  Hose Valve
>>>
>>> Awesome. So the "nominal" flow at 100 PSI will be 1,138.5 PSI?
>>>
>>> Maybe we need to change the hydraulic design method in the standard.
>>>
>>> Steve L.
>>>
>>>
>>> -------- Original message --------
>>> From: Brad Casterline <[email protected]>
>>> Date: 2/19/17 2:09 AM (GMT-08:00)
>>> To: Vince Sabolik <[email protected]>, [email protected]
>>> kler.org
>>> Subject: Re: K for a 2½" Hose Valve
>>>
>>> K=113.85
>>>
>>> In the same way that a nominal 1/2" sprinkler with a Coefficient of
>>> Discharge of .75 has a K=5.6, a nominal 2.5" hose valve with a Coefficient
>>> of Discharge of .61 has a K=113.85.
>>>
>>> Brad
>>> On Feb 17, 2017 8:28 AM, "Vince Sabolik" <[email protected]> wrote:
>>>
>>>> Good morning, everyone...
>>>>
>>>> Does anybody have a decent K Factor for a 2½" hose valve?
>>>>
>>>> Thanks!      Vince
>>>> <20914 x WTFP Logo NEW1.jpg>
>>>>
>>>> 11351 Pearl Road /  Suite 101
>>>> Strongsville, Ohio 44136
>>>> Phone 440 238-4800 <%28440%29%20238-4800> Fax 440 238-4876
>>>> <%28440%29%20238-4876> Cell 440 724-7601 <%28440%29%20724-7601>
>>>>
>>>>
>>>> * Vince Sabolik *
>>>>
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