maybe....... work backwards ..... Q = K (sqrt P) Q = 2.8 (sqrt 7) = 7.41 gallons or 74 sq ft of area.... [image: image.png] QR reduction Light Hazard? < 10' ceiling? 900 sq ft / 74 = 13 sprinklers or more in calc ......15 heads x 7.5 gallons = 120 gallons to 150 gallon demand in calc?
or do you have more heads is area? On Mon, Mar 27, 2023 at 12:08 PM Fpdcdesign <[email protected]> wrote: > I am working on a renovation to a college dormitory bathroom. The dorm > rooms are around the perimeter and the common bathroom is in the central > core. The college is replacing the existing partial height toilet and > shower partitions with full height partitions with full height doors. This > is in effect creating several small room, each requiring a sprinkler. The > number of sprinklers in this 410 sqft space is increasing from 4 to 15. > This will be a hydraulic nightmare. The rooms were designed to NFPA 13 > Residential and I have not yet found a calc sign that included the > bathroom. My guess is that the whole system would be undersized. > > Since this is not in a dwelling unit and is on a common corridor, 9.2.4.1 > does not apply. > > Room design does not work because all of the sprinklers are either in the > space or the communicating space. > > I have to calculate a 1500 sqft area in order to eliminate the sprinklers > in the stalls and showers. > > Per Chapter 12, residential sprinklers can only be used in dwelling units > and adjacent corridors, so that design is out. > > Any thoughts? > > Todd G Williams, PE > Fire Protection Design/Consulting > Stonington, CT > 860-535-2080 (ofc) > 860-554-7054 (fax) > 860-608-4559 (cell) > > _________________________________________________________ > SprinklerForum mailing list: > https://lists.firesprinkler.org/list/sprinklerforum.lists.firesprinkler.org > To unsubscribe send an email to > [email protected]
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