On Dec 9, 2009, at 12:41 , Antonio Beamud Montero wrote:
> s.intersect(select([tags.c.channel], tags.c.tag == tag))
This is returning a new select which is the intersection --- which you are
throwing away. It is *not* modifying s in-place.
You probably want to do
s = s.intersect(select([tags.c.channel], tags.c.tag == tag))
--
Alex Brasetvik
--
You received this message because you are subscribed to the Google Groups
"sqlalchemy" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/sqlalchemy?hl=en.
