Alex Brasetvik escribió:
> On Dec 9, 2009, at 12:41 , Antonio Beamud Montero wrote:
>
>
>> s.intersect(select([tags.c.channel], tags.c.tag == tag))
>>
>
> This is returning a new select which is the intersection --- which you are
> throwing away. It is *not* modifying s in-place.
>
> You probably want to do
>
> s = s.intersect(select([tags.c.channel], tags.c.tag == tag))
>
Ops.. thank you...
I've solved it using this approach:
lsel = []
for t in ltags:
lsel.append(select(.....))
xsec = intersect(*lsel)
Now it works perfect.
Greetings.
> --
> Alex Brasetvik
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