Correction:
res = {}
for hpoint in session.query(HistoryPoint).all():
res.setdefault(hpoint.vehicle_id, []).append({'id':hpoint.id,'location':
str(hpoint.location)})
But it will yield a dict, not an array of single-value dicts as requested
(are you sure this is what you want? anyways, it's trivial to change).
On Tuesday, September 22, 2015 at 8:33:13 PM UTC+3, Yegor Roganov wrote:
>
> Just do it in Python:
> res = []
> for hpoint in session.query(HistoryPoint).all():
> res.setdefault(hpoint.vehicle_id, []).append({'id':hpoint.id,'location'
> : str(hpoint.location)})
>
>
>
> On Tuesday, September 22, 2015 at 6:48:14 PM UTC+3, Johnny W. Santos wrote:
>>
>> Supose I have the models below, how could I query for a result like this:
>>
>> [
>> {1: [{"id": 3, "location": "POINT(23.23423423 54.234524234)"},{"id": 4,
>> "location": "POINT(23.23423423 54.234524234)"}]},
>> {2: [{"id": 45, "location": "POINT(78.23423423 43.234524234)"},{"id":
>> 67, "location": "POINT(34.2347683423 74.234524234)"}]},
>> ]
>>
>> The keys being the vehicle id and a list of HistoryPoints values.
>>
>> Supposing I have more fields in HistoryPoint and is prefered to query on
>> it due some filter conditions.
>>
>>
>> class Vehicle(Base):
>> id = Column(Integer, primary_key=True)
>> identifier = Column(Integer)
>>
>>
>> class HistoryPoint(Base):
>> vehicle_id = Column(Integer, FokeignKey('vehicles.id'))
>> location = Column(Geography('POINT'))
>>
>> vehicle = relationship('Vehicle', backref='history')
>>
>>
>> I'm really having a hard time on this, any help will be appreciated
>>
>> Johnny
>>
>
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