If the first loop exits with res3 == SQLITE_DONE then !result will be true and
the second loop should process exactly the same (assuming underlying data is
unchanged). I can’t see why the code below wouldn’t work although I’m confused
by the fact you say that sqlite3_step(stmt3) returns SQLITE_DONE immediately
after the sqlite3_reset(stmt3) but later say it’s returning 1 (SQLITE_ERROR).
int result = 0, res3 = SQLITE_OK;
for( ; ; )
{
res3 = sqlite3_step( stmt3 );
if( res3 == SQLITE_ROW )
{
// initial processing
}
else if( res3 == SQLITE_DONE )
break;
else
{
// error handling
result = 1;
}
}
if( !result )
{
res3 = sqlite3_reset( stmt3 );
for( ; ; )
{
res3 = sqlite3_step( stmt3 );
if( res3 == SQLITE_ROW )
{
// actual processing
}
else if( res3 == SQLITE_DONE )
break;
else
{
// error handling
}
}
}
Not sure where this code belongs
if( res3 != SQLITE_DONE )
break;
}
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