x,
On Mon, Jun 4, 2018 at 10:54 AM, x <[email protected]> wrote:
> If the first loop exits with res3 == SQLITE_DONE then !result will be true
> and the second loop should process exactly the same (assuming underlying data
> is unchanged). I can’t see why the code below wouldn’t work although I’m
> confused by the fact you say that sqlite3_step(stmt3) returns SQLITE_DONE
> immediately after the sqlite3_reset(stmt3) but later say it’s returning 1
> (SQLITE_ERROR).
Yes, first loop exits with the SQLITE_DONE.
The call to sqlite3_reset() return 0 (success).
But the very first call to sqlite3_step() returns 1 (error). Then the
code goes to execute error handling branch where it calls
sqlite3_errcode().
This function returns 0 - which I think means no error is encountered
during the previous SQLite call.
I can try to get an external error code or the error message though
using the appropriate function.
Thank you.
>
>
> int result = 0, res3 = SQLITE_OK;
> for( ; ; )
> {
> res3 = sqlite3_step( stmt3 );
> if( res3 == SQLITE_ROW )
> {
> // initial processing
> }
> else if( res3 == SQLITE_DONE )
> break;
> else
> {
> // error handling
> result = 1;
> }
> }
> if( !result )
> {
> res3 = sqlite3_reset( stmt3 );
> for( ; ; )
> {
> res3 = sqlite3_step( stmt3 );
> if( res3 == SQLITE_ROW )
> {
> // actual processing
> }
> else if( res3 == SQLITE_DONE )
> break;
> else
> {
> // error handling
> }
> }
> }
>
> Not sure where this code belongs
>
> if( res3 != SQLITE_DONE )
> break;
> }
>
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