On 09/21/2016 02:57 PM, Stepan Zakharov wrote:
Nothing & Nothing. Just returns SQLITE_OK, doesn't enter into Callback.
To avoid any doubts, when I change query to "select sql from sqlite_master where 
(type='table' AND name='TABLE_NAME');"
I do enter into Callback and have a result.
Perhaps, PRAGMA is somehow broken or disabled in my sqlite. But once again, it 
doesn't work nor on precompiled official binaries, neither on my own very 
straight-forward (without any special -D flags) compilation of amalgamation.
We are using VFS however, may be that can be ill-implemented somehow so it 
makes PRAGMA not to work..



What does your xFileControl() method return when it is passed SQLITE_FCNTL_PRAGMA?

It should usually return SQLITE_NOTFOUND (unless it is actually a pragma you want your VFS to intercept - bypassing the SQLite core). If it returns SQLITE_OK, I think you will get the behaviour you describe. Some docs here (search the page for "PRAGMA"):

https://www.sqlite.org/huawei-th3/uv/th3-392.c?mimetype=application/octet-stream

Dan.




I don't know what to think anymore.
It looks like will have to parse the SQL Create statement, eventually..

Date: Wed, 21 Sep 2016 13:47:41 +0700
From: danielk1...@gmail.com
To: sqlite-users@mailinglists.sqlite.org
Subject: Re: [sqlite] A problem with 'pragma table_info(...)'

On 09/21/2016 01:44 PM, Stepan Zakharov wrote:
Yes, of course it looks different.pragma table_info(TABLENAME);Where TABLENAME 
is my table name.I've tried it with single-quotes as well: pragma 
table_info('TABLENAME');No results in any case.And no errors. Returns 
SQLITE_OK.A very strange behaviour.
Does "PRAGMA table_info('sqlite_master');" return any results?

What does "PRAGMA compile_options;" say?

Dan.




To: sqlite-users@mailinglists.sqlite.org
From: clem...@ladisch.de
Date: Wed, 21 Sep 2016 08:27:32 +0200
Subject: Re: [sqlite] A problem with 'pragma table_info(...)'

Stepan Zakharov wrote:
it does not return any results
That is because the table name is not correctly quoted:

    sqlite> pragma table_info(...);
    Error: near ".": syntax error

Or does your statement look different?


Regards,
Clemens
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