Hi Luke, I now see what you mean. The sketch makes it clear. The sun moves along the declination line. The angle the declination line makes with the horizon (Psi) is obviously LFS. From that perspective, the side FS along the horizon line is the azimuth from south. The angle of the meridian with the horizon, LSF is 90 degrees. Our perspectives were different. I was focused on the traditional Navigation Triangle, ZPF. Your perspective is that of an observer at the center C looking out to the horizon. Your assumption that LSF is angle Psi is much more apparent than my assumption that it is the third angle of the triangle PFZ.
You win the Psi Challenge. Roger Bailey At 07:52 AM 9/28/99 -0800, you wrote: >Roger Bailey wrote: >> >> Sorry but I do not see the basis for these assumptions. > >Hi Roger, > >So again looking at fig.26 in Smart, >segment LF is by definition angle LPF (the HA) and segment SF is by >definition angle SZF (the AZI) lastly, the intersection of LF and SF is >the angle of interest (psi). I hope this helps in seeing my solution. > >Best, > >Luke >
