Hi Dave,

I agree with your logic, looking at the equatorial disc where the hour angles 
are true, equal to 15° per hour and the gnomon line as a point, the same point 
on this plane as the intersection point discussed. The gnomon point becomes a 
line in other projections, but the geometric point projects remains as an 
intersection point of the hypotenuse lines of hour triangles 6 hours apart. 

This drawing evoked in my mind the construction techniques of Durer and 
Zarbula, techniques of descriptive geometry now bypassed by trig 
transformations in computer programs, useful but only understood by their 
creators. I appreciate Fer de Vries for making his logic and not just his 
design program available. See "A Universal Method to Compute Flat Sundials" 
http://www.de-zonnewijzerkring.nl/eng/index-vlakke-zonw.htm

Regards,
Roger Bailey
Walking Shadow Designs

From: Dave Bell 
Sent: Sunday, February 03, 2013 4:51 PM
To: [email protected] 
Subject: RE: I found out (graphic) a theorem


I believe I may have the answer here. Can't formally prove it yet, but it makes 
sense.

 

Returning to the most basic sundial, the equatorial, the hour angles are equal, 
and hours differing by 6 have hour angle lines at 90°.

Inscribing any right triangle in a circle (the equatorial plane), the 
hypotenuse of the triangle will always be a diameter.

All diameters intersect in a single point, the center of the circle.

 

When the circular equatorial dial is projected on a non-equatorial plane, the 
equatorial circle becomes an ellipse.

The hour angle pair chords must still intersect, even though the angles at the 
origin of the dial are no longer necessarily right angles.

The common intersection point on the (horizontal, e.g.) dial is the projection 
of the center of the equatorial dial.

 

Dave

 


--------------------------------------------------------------------------------

From: sundial [mailto:[email protected]] On Behalf Of Willy Leenders
Sent: Sunday, February 03, 2013 2:11 PM
To: Sundial sundiallist
Subject: I found out (graphic) a theorem

 

In his book "Die Sonnenuhr und ihre Theorie" (The sundial and his theory) Jörg 
Meyer writes on page 200 (my English translation):

 

I found the following remarkable theorem  in the book of Heinz Schilt. 'Ebene 
Sonnenuhren' (Plane sundials)

 

Through the point P where all the hour lines of any sundial come together, a 
circle is drawn.

The center M and the radius of the circle are irrelevant.

The hour lines whose hour angle differ from each 6 hours or 90 ° were grouped 
into pairs.

The points where the hour lines of a pair intersect the circle, are connected 
with a chord (a straight line joining the ends of an arc )

Then is applicable: all these chords pass through a common point Q.

 



 

 

In the study of this case and assuming that the projection of a circle is an 
ellipse and vice versa,  I found out (graphic) the theorem:

 

Of all right triangles, inscribed in an ellipse, of which the right angle point 
(point P) is common, the hypotenuses intersect in the same point (point S).


See drawing.

 

 

I found that theorem never formulated, certainly no proof.


Who can prove this theorem?

 



 

 

 

 

 

Willy Leenders

Hasselt in Flanders (Belgium)

 

Visit my website about the sundials in the province of Limburg (Flanders) with 
a section 'worth knowing about sundials' (mostly in Dutch): 
http://www.wijzerweb.be

 

 

 

 






 



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