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I hope I can give you an explaination in english,
because I am from Holland :
You start with the amount of NaOH you used to
make your batch of BD.
For example 5 kg for 800 liters of BD.
So you use 5 kg NaOH, which you will all find back
in the bottom layer residue.
1 mole of NaOH weighs 23 + 16 + 1 makes 40
grams.
23 + 16 + 1 are the mole weights of the elements.
You can find them in te periodic system of elements in every schoolbook of
chemistry.
Now you mix with phosphoric acid, but what
percentage ?
Phosphoric acid is H3PO4, which has a mole weight
of (3x1) + 31 + (4x16) =98 grams
What you should try to reach is a complete reaction
between the acid and the NaOH
The reaction would be : H3PO4 +NaOH --> Na3PO4 +
H20
Now make it equal, so it gets to :
H3PO4 + 3NaOH --> Na3PO4 + 3H2O
In grams :
((3x1)+16+64) + (3x40)
--> ((3x23)+16+64) + (3x18) ---------> 203 = 203
So the reaction is equal now.
That means you need one mole of H3PO4 + 3 moles of
NaOH to react completely and split your residue.
As you will understand now, I hope, you need 98
grams of H3PO4 for every 40 grams of NaOH you used.
Of course if you have a phosphoric acid of let's
say 75%, it means that if you take 1 kilo of that, you have 750 grams of
phosphoric acid.
All together, if you don't take enough acid, you
won't split your residue completely, but if you take too much acid, you will
find the surplus somewhere in the FFA's , or maybe on the bottom, or
maybe solved in either of them, or maybe.........
I hope I helped you with this.
Greetings,
Pieter
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