If I understand you right, I need to look at where the parabola exits the view window, calculate the tangent lines to the parabola at those points, and then find the intersection of these 2 lines?
Peter --- In [email protected], "pilatfr" <[EMAIL PROTECTED]> wrote: > > --- In [email protected], "hubby2debbie" > <[EMAIL PROTECTED]> wrote: > > Example > http://pilat.free.fr/english/svg/parabole_bezier.htm > > You search intersections of parabola with canvas. Control point is > intersection of tangents in this points > > Michel > > > Hi, my name is Peter, and I just found this group. I want to draw an > > accurate parabola when I have its equation. The math is no problem > for > > me, I just need to know how to find the control point for the > quadratic > > curve. Actually, I can figure out the x-coordinate of the point, but > > I'm not sure how to figure out the y-coordinate. Any help would be > > appreciated. > > > > Peter ----- To unsubscribe send a message to: [EMAIL PROTECTED] -or- visit http://groups.yahoo.com/group/svg-developers and click "edit my membership" ---- Yahoo! Groups Links <*> To visit your group on the web, go to: http://groups.yahoo.com/group/svg-developers/ <*> To unsubscribe from this group, send an email to: [EMAIL PROTECTED] <*> Your use of Yahoo! Groups is subject to: http://docs.yahoo.com/info/terms/
