Austin do we really need this 3rd proposal? This makes my original one really a waste of time. I was trying to solve https://openradar.appspot.com/20990743 with the original `Any<>` proposal when Swift 3 ships. Your other proposal would enhance it without introducing breaking changes.
To that end, I’d suggest Any<>,Any<Any, XX>, and Any<Any<XX>> all cause warnings. Why would these cause warnings? func foo(any: protocol<>) func foo(any: protocol<Any>) func foo(any: protocol<Any, ProtocolA>) func foo(any: protocol<ProtocolA>) Everything is already fine today. -- Adrian Zubarev Sent with Airmail Am 19. Mai 2016 bei 08:55:54, David Waite via swift-evolution ([email protected]) schrieb: My feedback is that we should narrow what is acceptable for Any as much as possible, because relaxing restrictions in the future won’t break existing code. To that end, I’d suggest Any<>,Any<Any, XX>, and Any<Any<XX>> all cause warnings. -DW > On May 19, 2016, at 12:43 AM, Austin Zheng <[email protected]> wrote: > > Does anyone want to speak up in favor of 'Any<>'? The more I think about it > the more I think 'Any' should just be the single, canonical form. > > Austin > > >> On May 18, 2016, at 11:33 PM, Colin Barrett <[email protected]> >> wrote: >> >> There's no need for this, that's what I was trying to get across. It's >> (likely) a special case in the grammar right now. If we eliminate Any<>, >> from the point of view of syntax, both Any and Any<Foo, Bar> are just a >> built in type and normal application of generic arguments (to a built in >> type). >> >> -Colin (via thumbs) >> >>> On May 19, 2016, at 1:58 AM, Austin Zheng <[email protected]> wrote: >>> >>> - 'Any<>' should be allowed. You can currently use 'protocol<>' in your >>> code instead of 'Any'. > _______________________________________________ swift-evolution mailing list [email protected] https://lists.swift.org/mailman/listinfo/swift-evolution
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