Making SomeClass conform to Equatable should fix it:
class SomeClass : Equatable {
static public func ==(_ lhs:SomeClass, _ rhs:SomeClass) -> Bool {
return lhs === rhs
}
}
/Jens
On Sun, Jul 9, 2017 at 5:11 PM, David Baraff via swift-users <
swift-users@swift.org> wrote:
> Given 2-tuples of type (T1, T2), you should be able to invoke the ==
> operator if you could on both types T1 and T2, right? i.e.
>
> (“abc”, 3) == (“abc”, 4) // legal
>
> but:
>
> class SomeClass {
> static public func ==(_ lhs:SomeClass, _ rhs:SomeClass) -> Bool {
> return lhs === rhs
> }
> }
>
> let c1 = SomeClass()
> let c2 = SomeClass()
>
> let t1 = ("abc", c1)
> let t2 = ("abc", c2)
>
> c1 == c2 // legal
> t1 == t2 // illegal
>
>
>
>
> Why is t1 == t2 not legal given that c1 == c2 IS legal?
>
>
>
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> swift-users@swift.org
> https://lists.swift.org/mailman/listinfo/swift-users
>
>
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