Easy: class SomeClass : Equatable {
--
Adrian Zubarev
Sent with Airmail
Am 9. Juli 2017 um 17:11:14, David Baraff via swift-users
(swift-users@swift.org) schrieb:
Given 2-tuples of type (T1, T2), you should be able to invoke the == operator
if you could on both types T1 and T2, right? i.e.
(“abc”, 3) == (“abc”, 4) // legal
but:
class SomeClass {
static public func ==(_ lhs:SomeClass, _ rhs:SomeClass) -> Bool {
return lhs === rhs
}
}
let c1 = SomeClass()
let c2 = SomeClass()
let t1 = ("abc", c1)
let t2 = ("abc", c2)
c1 == c2 // legal
t1 == t2 // illegal
Why is t1 == t2 not legal given that c1 == c2 IS legal?
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