Comment #8 on issue 636 by ondrej.certik: integrate(1/(x**2+1)) should  
return arctan(x)
http://code.google.com/p/sympy/issues/detail?id=636

Here is what mathematica does:

http://integrals.wolfram.com/index.jsp?expr=1%2F(1%2Bx^5)&random=false

             1
Integrate[------, x] ==
                5
           1 + x


(-2 Sqrt[10 - 2 Sqrt[5]]

              1 + Sqrt[5] - 4 x
      ArcTan[--------------------] +
             Sqrt[10 - 2 Sqrt[5]]

     2 Sqrt[2 (5 + Sqrt[5])]

              -1 + Sqrt[5] + 4 x
      ArcTan[---------------------] + 4 Log[1 + x] +
             Sqrt[2 (5 + Sqrt[5])]

                            (-1 + Sqrt[5]) x    2
     (-1 + Sqrt[5]) Log[1 + ---------------- + x ] -
                                   2

                           (1 + Sqrt[5]) x    2
     (1 + Sqrt[5]) Log[1 - --------------- + x ]) / 20
                                  2



Btw, I think our pretty printing looks much better! :)

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