Comment #81 on issue 1694 by nicolas.pourcelot: solve has many issues with
fractions
http://code.google.com/p/sympy/issues/detail?id=1694
There is at least one drawback with sets:
In [8]: 1 == S.One
Out[8]: True
In [9]: [1] == [S.One]
Out[9]: True
In [10]: set([1]) == set([S.One])
Out[10]: False
This is because sets use hash for fast comparison, and hash(1) !=
hash(S.One).
(To solve this, S.Integer.__hash__ should be modified to return the integer
own value...)
--
You received this message because you are subscribed to the Google Groups
"sympy-issues" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/sympy-issues?hl=en.