Status: New
Owner: ----
Labels: Type-Enhancement Priority-Medium Solvers
New issue 3194 by [email protected]: Implement "show steps" for solvers
http://code.google.com/p/sympy/issues/detail?id=3194
Wolframalpha have a nice function
which can show the steps of solving equation:
solve(x^2 + (-r - 1)*x + r, x)
Result: x == 1 || x == r
Show steps.
Possible intermediate steps:
(-r-1) x+r+x^2 = 0
Subtract r from both sides:
(-r-1) x+x^2 = -r
Add 1/4 (-r-1)^2 to both sides:
(-r-1) x+1/4 (-r-1)^2+x^2 = 1/4 (-r-1)^2-r
Factor the left hand side:
(1/2 (-r-1)+x)^2 = 1/4 (r^2-2 r+1)
Take the square root of both sides:
abs(1/2 (-r-1)+x) = 1/2 sqrt(r^2-2 r+1)
Eliminate the absolute value:
1/2 (-r-1)+x = -1/2 sqrt(r^2-2 r+1) or 1/2 (-r-1)+x = 1/2 sqrt(r^2-2
r+1)
Subtract 1/2 (-r-1) from both sides:
x = 1/2 (1-sqrt((-1+r)^2)+r) or 1/2 (-r-1)+x = 1/2 sqrt(r^2-2 r+1)
Subtract 1/2 (-r-1) from both sides:
x = 1/2 (1-sqrt((-1+r)^2)+r) or x = 1/2 (1+sqrt((-1+r)^2)+r)
Is it possible to have this function in sympy?
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