Thanks for all the responses,
you bring up a good argument about some of the additional
complications of simplifcation depending on some of the potential
factors of the Symbol. I appreciate your thoughtfullness on this
response.


on a similar note what is the best way to replace an expression that
has 1.0s everywhere

In [36]: print 1.0*a**1.0
1.0*a**1.0

this seems to be the simplest:

In [37]: print (1.0*a**1.0).subs(1.0, 1)
a


On Jan 10, 2:41 pm, "Alexey U. Gudchenko" <[email protected]> wrote:
> 11.01.2012 00:27, [email protected] пишет:
>
> > On the other hand I don't know why a**2.0/a is not a**1.0. This seems like
> > a bug...
>
> However, the 'simplify' works for this case:
>
> In [3]: simplify(a**2.0/a)
> Out[3]: a**1.0
>
> Remarks:
> We implicitly assume that a<>0 during this simplification.
>
> If e.g.
>
> >>> a = Symbol('a', positive=True)  # then 'a' became to be 'real' too
>
> then this simplification can be automatic, I think. At least I have no
> objection to add the last case to the issue tracker.
>
> --
> Alexey U.

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