cross posting again:
OK, then what we should have is amu = amus = g/mol so when you divide
mass by amu you get mols. If you want the number you multiply by
avogadro('s constant) to get 6e23 (for 1 mol):
>>> from sympy.physics import units as u
>>> amu=u.g/u.mol
>>> u.g/amu
mol
>>> _*u.avogadro
602214179000000000000000
I think this is all consistent: a mol (like dozen) is a number;
mass/mass gives a number; when you use SI mass and amu you will get
the number in terms of mol; if you want to see the actual number (like
converting dozen to 12) you multiply by avogadro('s constant).
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