Hmm, I might be missing something, but it seems to me that that is not addressing the particular point I asked about, namely that the current behavior of the n=None lazy term generation does not yield 0 whenever there is no contribution at a particular order.
On Sep 13, 2012, at 11:15 AM, Chris Smith wrote: > On Thu, Sep 13, 2012 at 6:52 AM, nikolas <[email protected]> wrote: >> Follow-up: I think I have found a way that works. >> I guess if one is interested in expanding about 0, one can simply do >>>>> f = x + 5 * x**3 >>>>> coeffs = reversed(series(f, x, 0, n = 4).as_poly(x).all_coeffs()) >>>>> list(coeffs) >> [0, 1, 0, 5] >> >> So, to expand about x0!= 0, I can substitute x->x0 + x1 and expand in orders >> of x1. >> If this is a bad way to do it, please let me know! > > I wrote about this in the docstring of Expr.series, I believe. Try > "help(Expr.series)". > > -- > You received this message because you are subscribed to the Google Groups > "sympy" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/sympy?hl=en. > -- You received this message because you are subscribed to the Google Groups "sympy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sympy?hl=en.
