On Sep 12, 2012, at 10:31 PM, Chris Smith <[email protected]> wrote:

> On Thu, Sep 13, 2012 at 6:27 AM, nikolas <[email protected]> wrote:
>> Hey guys,
>>
>> for a series expansion of some function f(x) about some point x0 up to order
>> n+1, I would like to easily generate the sequence of all coefficients.
>> I.e. if we have
>>
>> f(x) = a0 + a1 * (x-x0) + a2 * (x-x0)**2 + ... + an (x-x0)**n + O((x-x0)**n)
>>
>> is there a straightforward way to obtain a generator for the sequence a0,
>> a1, a2, ... an that includes the non-zero terms?
>
>
> Part of the problem of including this in general is that in general
> the exponents need not be integers and if you got a list of
> coefficients, how would you know what terms they went with.
>
>>>> series(sqrt(x)/(x+sin(x)), x)
> 1/(2*x**(1/2)) + x**(3/2)/24 + x**(7/2)/720 - x**(11/2)/120960 + O(x**6)
>
> Above, the powers are -1/2+2*i for i in range(n). If one had a series
> object then one of its methods might be "coeffs" and such a method
> might first return (-1/2, 2) -- the first exponent and the step size
> -- followed by the coefficients, 1/2, 1/24, 1/720, -1/120960. But that
> seems a little complicated.

Actually, this can be useful, but you're right that it is nontrivial.
See https://github.com/sympy/sympy/wiki/UD-series and
https://github.com/sympy/sympy/wiki/UD-Sequences-and-formal-power-series-prototype
for (mostly Alexey's) ideas on this.

And by the way, even if the exponents are integers, they won't be
positive integers if you expand around a pole, and that gives the same
issue.

Aaron Meurer

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