Multiplying through by lambda and taking terms independent of i from the
sum, I seem to get 4 \sum x_i = n(lambda^2 - 6\lambda). This is just a
quadratic equation for lambda.
Am I missing something?
Best,
Tom
On 21.02.2013 18:31, Matthew Rocklin wrote:
I need to solve the following problem for lambda.
n
____
╲
╲ 2
╲ - λ + 6⋅λ + 4⋅xᵢ
╱ ───────────────── = 0
╱ 4⋅λ
╱
‾‾‾‾
i = 1
This is the end of a simplification around a data-oriented problem. In
the future I will be given a set of many `x_i`s as data and will be
asked to solve for lambda. I'm trying to make this future computation
as simple as possible.
Can SymPy help me to reduce this problem any further? (it has already,
by the way, done wonders.)
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