I think the only thing that is missing is that summation does not
automatically split out parts that it can do.
https://code.google.com/p/sympy/issues/detail?id=2297 is also relevant
here.

Aaron Meurer

On Thu, Feb 21, 2013 at 11:39 AM, Matthew Rocklin <[email protected]> wrote:
> Ah, yes, that is helpful.
>
> In general I'm looking for an automated solution for problems like this.
> I'd like to solve this problem without being smart :)
>
>
> On Thu, Feb 21, 2013 at 10:35 AM, Tom Bachmann <[email protected]> wrote:
>>
>> Multiplying through by lambda and taking terms independent of i from the
>> sum, I seem to get 4 \sum x_i = n(lambda^2 - 6\lambda). This is just a
>> quadratic equation for lambda.
>>
>> Am I missing something?
>>
>> Best,
>> Tom
>>
>>
>> On 21.02.2013 18:31, Matthew Rocklin wrote:
>>>
>>> I need to solve the following problem for lambda.
>>>
>>>    n
>>>   ____
>>>   ╲
>>>    ╲      2
>>>     ╲  - λ  + 6⋅λ + 4⋅xᵢ
>>>     ╱  ───────────────── = 0
>>>    ╱          4⋅λ
>>>   ╱
>>>   ‾‾‾‾
>>> i = 1
>>>
>>> This is the end of a simplification around a data-oriented problem.  In
>>> the future I will be given a set of many `x_i`s as data and will be
>>> asked to solve for lambda.  I'm trying to make this future computation
>>> as simple as possible.
>>>
>>> Can SymPy help me to reduce this problem any further?  (it has already,
>>> by the way, done wonders.)
>>>
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>>
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