Yes, as I mentioned, it was fixed only in the development version. You
can see what version you have by

import sympy
print sympy.__version__

If you want to run the development version, read
https://github.com/sympy/sympy/wiki/Getting-the-bleeding-edge.

Aaron Meurer

On Wed, Apr 3, 2013 at 11:58 PM, ThanhVu Nguyen
<[email protected]> wrote:
> l is a variable which is not assigned to any value
> In [90]: from sympy.abc import l,u
>
> In [91]: (l<=0).subs({l:oo})
> Out[91]: True
>
> In [92]: (l<=0).xreplace({l:oo})
> Out[92]: True
>
> My sympy is the latest "stable" one (how do I check the exact version number
> anyway?) but not the development version.  Perhaps this bug has been fixed
> in the development branch ?
>
>
>
> On Wednesday, April 3, 2013 11:44:13 PM UTC-6, smichr wrote:
>>
>> Make sure sympy is up to date. I get (with the development version):
>>
>> >>> (l<=0)
>> l <= 0
>> >>> _.subs(l,oo)
>> False
>> >>> (l<=0).subs({l:oo})
>> False
>>
>> If it is current, check your value of `l` -- maybe it is -1 or something.
>> There are some IOs that are missing and I'm not sure what may have happened
>> in them.
>
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