Yes, 1/(x + y) is not a polynomial, or at least not any any variables
that it can guess at.  So that exception is correct.

Aaron Meurer

On Tue, Jun 25, 2013 at 2:35 AM, Sébastien Boisgérault
<[email protected]> wrote:
> Aaron,
>
> I installed sympy from the git repository.
>
> The same call
>
>     poly(1/(x+y), z, domain="EX")
>
> now generates a:
>
>     sympy.polys.polyerrors.GeneratorsError: you have to provide generators
> because EX domain was requested
>
> But
>
>     Poly(1/(x+y), z, domain="EX")
>
> works fine (it's probably what I should have done from the start).
>
> Thanks for the help.
>
> SB
>
>
>
>
>
> Le lundi 24 juin 2013 11:29:55 UTC+2, Sébastien Boisgérault a écrit :
>>
>> Hi all,
>>
>>
>> With symbols x, y and z imported from sympy.abc, the call
>>
>>     >>> poly(1/(x+y), z, domain="EX")
>>
>> generates a ValueError, while on the other hand, definitions like
>>
>>     >>> poly(1/x, z, domain="EX")
>>
>> and even
>>
>>     >>> poly(1/(sqrt(x+y)), z, domain="EX")
>>
>> are just fine.
>>
>> Is it a known issue (I am using sympy version 0.7.1.rc1) ?
>>
>> Am I missing something obvious ?
>>
>>
>> Cheers,
>>
>> SB
>
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