On Wed, Dec 04, 2013 at 11:11:31AM -0700, Aaron Meurer wrote:
> I just checked evalf and it returns the right answers, inf and -inf.
> So apparently it's smarter than I had thought.
In [1]: r1 = x**3 - 3*x
In [2]: r2 = -x - 1
In [3]: r1.evalf(subs={x: oo})
Out[3]: +inf
But the second case:
In [4]: r2.evalf(subs={x: oo})
Out[4]: +inf
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