These little issues with the transpose are the reason this isn't
implemented yet.

Aaron Meurer

On Mon, Apr 28, 2014 at 2:18 PM, Tim Lahey <[email protected]> wrote:
> It's only 2*A*x is A is symmetric (A.T = A). Otherwise it's (A.T + A). That 
> said, I don't think Matrix Expressions support derivatives at the moment.
>
> Cheers,
>
> Tim.
>
> On 2014-04-28, at 1:27 PM, Gustavo <[email protected]> wrote:
>
>> Can I have matrices and vectors A and x with compatible but unspecified 
>> dimensions. And get diff(x.T * A * x , x) return 2*A*x ?
>>
>> Thanks,
>> Gustavo
>
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