I agree, this could be helpful to many people. But first let's make sure we
iron out all the bugs.
And then I suppose one could re-write the expressions in a more
user-friendly form?
What do you propose, Chris?
On Friday, June 6, 2014 2:16:15 PM UTC+2, Christophe Bal wrote:
>
> Hello.
>
> All the receipts in this dicussion look very interesting.Maybe all of this
> ones could be put in the official documentation.
>
>
> Christophe BAL
>
>
> 2014-06-06 13:34 GMT+02:00 Andrei Berceanu <andreib...@gmail.com
> <javascript:>>:
>
>> The unflatten_mul function factorized the 2, but not the g, i.e. it
>> returns
>>
>> 2(g*|psi1|**2 + g*|psi2|**2)
>>
>> instead of
>>
>> 2g*(|psi1|**2 + |psi2|**2)
>>
>>
>> On Friday, June 6, 2014 1:07:26 PM UTC+2, F. B. wrote:
>>
>>>
>>>
>>> On Friday, June 6, 2014 12:22:14 PM UTC+2, Andrei Berceanu wrote:
>>>>
>>>> Tnx!
>>>> I think there is an error in the line (unbalanced paranthesis):
>>>>
>>>> return node.xreplace ({e: S.One, conjugate(e): S.One})*abs(e)**2)
>>>>
>>>>
>>> Yes, sorry, just remove the last parenthesis.
>>>
>>>
>>>
>>>> Also, do you know how I can force the factorization of the 2*g to get
>>>> 2*g(|psi1|**2 + |psi2|**2)?
>>>>
>>>>
>>> Try this one:
>>>
>>> import collections
>>>
>>> def unflatten_mul(node):
>>> d = collections.defaultdict(lambda: [])
>>> new_args = []
>>> for arg in node.args:
>>> if arg.args and arg.args[0].is_Number:
>>> d[arg.args[0]].append(arg.func(*arg.args[1:]))
>>> continue
>>> new_args.append(arg)
>>> print d
>>> for key, item in d.items():
>>> new_args.append(Mul(key, Add(*item), evaluate=False))
>>> return node.func(*new_args, evaluate=False)
>>>
>>>
>>> apply this function on *expr*, it should work.
>>>
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