I have no special ideas to propose except to start with the examples in
this discussion. Maybe different working methods can be shown.
2014-06-06 14:23 GMT+02:00 Andrei Berceanu <andreiberce...@gmail.com>:
> I agree, this could be helpful to many people. But first let's make sure
> we iron out all the bugs.
> And then I suppose one could re-write the expressions in a more
> user-friendly form?
> What do you propose, Chris?
>
>
> On Friday, June 6, 2014 2:16:15 PM UTC+2, Christophe Bal wrote:
>
>> Hello.
>>
>> All the receipts in this dicussion look very interesting.Maybe all of
>> this ones could be put in the official documentation.
>>
>>
>> Christophe BAL
>>
>>
>> 2014-06-06 13:34 GMT+02:00 Andrei Berceanu <andreib...@gmail.com>:
>>
>>> The unflatten_mul function factorized the 2, but not the g, i.e. it
>>> returns
>>>
>>> 2(g*|psi1|**2 + g*|psi2|**2)
>>>
>>> instead of
>>>
>>> 2g*(|psi1|**2 + |psi2|**2)
>>>
>>>
>>> On Friday, June 6, 2014 1:07:26 PM UTC+2, F. B. wrote:
>>>
>>>>
>>>>
>>>> On Friday, June 6, 2014 12:22:14 PM UTC+2, Andrei Berceanu wrote:
>>>>>
>>>>> Tnx!
>>>>> I think there is an error in the line (unbalanced paranthesis):
>>>>>
>>>>> return node.xreplace ({e: S.One, conjugate(e): S.One})*abs(e)**2)
>>>>>
>>>>>
>>>> Yes, sorry, just remove the last parenthesis.
>>>>
>>>>
>>>>
>>>>> Also, do you know how I can force the factorization of the 2*g to get
>>>>> 2*g(|psi1|**2 + |psi2|**2)?
>>>>>
>>>>>
>>>> Try this one:
>>>>
>>>> import collections
>>>>
>>>> def unflatten_mul(node):
>>>> d = collections.defaultdict(lambda: [])
>>>> new_args = []
>>>> for arg in node.args:
>>>> if arg.args and arg.args[0].is_Number:
>>>> d[arg.args[0]].append(arg.func(*arg.args[1:]))
>>>> continue
>>>> new_args.append(arg)
>>>> print d
>>>> for key, item in d.items():
>>>> new_args.append(Mul(key, Add(*item), evaluate=False))
>>>> return node.func(*new_args, evaluate=False)
>>>>
>>>>
>>>> apply this function on *expr*, it should work.
>>>>
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