On Thursday, September 3, 2015 at 8:54:54 AM UTC+3, Carl Sandrock wrote:
>
> If I do
>
> import sympy
> k, V, Vprime = sympy.symbols('k, V, Vprime')
> print sympy.diff(k + V(t), t)
>
> I get Derivative(V(t), t) as I expect - the derivative distributes and
> the constant term has zero derivative.
>
> However, if I construct an equivalent expression via substitution,
> simplify does not distribute the derivative. How can I get the same
> result via substitution as when I evaluate the expression directly?
>
> sympy.diff(Vprime(t)).subs({Vprime(t): k + V(t)}).simplify()
>
> returns Derivative(k + V(t), t).
>
>
> Perhaps you could use ``doit()``` instead of ``simplify()``.
>
>
>
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