On Thursday, September 3, 2015 at 9:18:35 AM UTC+2, Kalevi Suominen wrote:
>
>
>
> On Thursday, September 3, 2015 at 8:54:54 AM UTC+3, Carl Sandrock wrote:
>>
>> If I do
>>
>> import sympy
>> k, V, Vprime = sympy.symbols('k, V, Vprime')
>> print sympy.diff(k + V(t), t)
>>
>> I get Derivative(V(t), t) as I expect - the derivative distributes and
>> the constant term has zero derivative.
>>
>> However, if I construct an equivalent expression via substitution,
>> simplify does not distribute the derivative. How can I get the same
>> result via substitution as when I evaluate the expression directly?
>>
>> sympy.diff(Vprime(t)).subs({Vprime(t): k + V(t)}).simplify()
>>
>> returns Derivative(k + V(t), t).
>>
>>
>> Perhaps you could use ``doit()``` instead of ``simplify()``.
>
>>
>>
>>
That worked perfectly, thank you very much!
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