Hello, For a project I'm currently working on, I need to draw some parametrized shape. To achieve that I compute the complex coordinate of each point. The problem is that some shape are quiet complex and it's sometime hard to find the point's coordinate as a function of our parameters. To save some time for the next shape, I want to use SymPy to compute these coordinates. The idea would be to adapt validated equation system to describe the new shapes. So I tried this (simple) example :
<https://lh3.googleusercontent.com/-moYFl6lqX7Y/VgPHcVw3_-I/AAAAAAAAAEs/U6JN5L5gNVY/s1600/55ifamhm.bmp> with the following code (with the simplification P1 above P0 ie same reel part) *#Point to find (P0 to P5 only, P6 to P10 are found by symmetry)* *var("P:6", complex=True)* * #Available data* H0, H1, H2, W0, W1, W2, Rbo =symbols ('H0, H1, H2, W0, W1, W2, Rbo', real= True,*positive=True) * *#Equation to solve* *Eq_list = list()* *Eq_list.append(P0 - Rbo)* Eq_list.append(P1 - P0*-1j*W0/2.0)* *Eq_list.append(P2 - P1 - H0)* Eq_list.append(P3 - P2 - H1*-1j*(W1-W0)/2.0)* *Eq_list.append(P4 -P2 - H1)* Eq_list.append(P5 - P4 -H2-1j*(W2-W0)/2.0) result = solve (Eq_list,[P0, P1,* P2, P3, P4, P5])* The result is as expected : P0 = Rbo P1 = Rbo + 0.5*I*W0 P2 = H0 + Rbo + 0.5*I*W0 P3 = H0 + H1 + Rbo + 0.5*I*W1 P4 = H0 + H1 + Rbo + 0.5*I*W0 P5 = H0 + H1 + H2 + Rbo + 0.5*I*W2 Now I want to remove my simplification (P1 must be on the circle, so it's not exactly above P0). So I change my equations for P1 this way : Eq_list.append(Abs(P1) - Rbo) Eq_list.append(im(P1)-im(P0)-W0/2.0) The first equation states that P1 is on the circle of center (0,0) and radius Rbo, and the second one that P1 is on a line parallel to the abscissa passing by a point P0+1j*(W0/2). The expected result is : P1 = P0 * exp(1j*arcsin(W0/(2*Rbo))) #Or P1 = Rbo * exp(1j*arcsin(W0/(2*Rbo))) And I get (I'm using Python 2.7 and SymPy 0.7.6) : NotImplementedError: solving Abs(P1) when the argument is not real or imaginary. So the first thing I want to know is : I am doing this right ? Maybe my problem is just due to the fact that there are two solutions for P1 and that I need to state Re(P1) >0 (if it is possible). Or maybe be there is a better way to solve this kind of problem with SymPy (adding other assumption or equation, working with variables for both real and imaginary part of each point, using another function or module I'm not knowing about...). Anyway, having a way to specify distance and angle between some points directly with the functions "Abs" and "arg" would be really helpful to solve this kind of problem. So I'm wondering, how hard would it be to implement the use of Abs and arg in your solver ? If it's at my reach I'm ready to implement it myself (with some help and workaround of course). Best Regards, Pierre Bonneel -- You received this message because you are subscribed to the Google Groups "sympy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sympy. To view this discussion on the web visit https://groups.google.com/d/msgid/sympy/63263335-741c-4fa5-875b-8038f1b8b8e1%40googlegroups.com. For more options, visit https://groups.google.com/d/optout.
