I found the issue https://github.com/sympy/sympy/issues/6835.

Aaron Meurer

On Tue, Feb 16, 2016 at 2:39 PM, Aaron Meurer <[email protected]> wrote:
> The problem here isn't so much to do with trig identities as the big
> numbers. The issue is that things like
> factorial(847937526693730893984732849857349) and
> 1342**(87236487262873**(8732498237693269832+3)+5)-1) evaluate
> automatically, which causes Python to try to compute them until the
> memory fills up and it crashes.
>
> The way I would fix this is to create a special BigInteger object,
> which would wrap large integers and avoid explicit computation. For
> example, BigInteger(10)**BigInteger(10)**BigInteger(100) would remain
> unevaluated. It would then use some algorithms and the assumptions
> system to compute facts. So something like
> factorial(BigInteger(847937526693730893984732849857349)).is_integer
> would be True, which would be enough for
> sin(pi*factorial(BigInteger(847937526693730893984732849857349))) to
> simplify.  There are some cool things that you could do with this,
> like (2**BigInteger(74207281) - 1).is_prime. For anyone interested,
> there's probably enough cool stuff that could be done here for a GSoC
> project.
>
> (By the way, I had an issue open in the issue tracker a while ago
> about this, but I can't find it)
>
> Aaron Meurer
>
> On Tue, Feb 16, 2016 at 2:02 PM, Jari-Pekka Ikonen
> <[email protected]> wrote:
>> Some trigonometric expressions can easily and quickly be simplified without
>> ever calculating some of the functions in it just by using the known
>> properties of the functions in the expression.
>>
>> For example:
>>
>> sin(2*pi)
>>
>> is 0. So:
>>
>> sin(pi*factorial(847937526693730893984732849857349))
>>
>> is also 0. This does not require calculation of the factorial, but the
>> property knowledge, that the result of the factorial is an even integer.
>>
>> There are several other examples of expressions, like:
>>
>> tan(pi*(1342^(87236487262873^(8732498237693269832+3)+5)-1))
>>
>> is also 0. Several others:
>>
>> cos(pi*(factorial(8629264243264^64862423642638763847)+1/2))
>>
>> is 0.
>>
>> Could this be implemented in sympy? So many other examples would be much
>> faster to calculate.
>>
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