factor(sym.Derivative( (sin(t)+exp(t))**3 , t ).doit())
works, but it would still be nice if someone could tell me, if there is way
to turn the simplification of ;)
Am Mittwoch, 1. Juni 2016 15:34:28 UTC+2 schrieb Michi S:
>
> Hello!
>
> Is there a way to turn off the automatic simplification by calculating the
> derivative of a function? For example
>
> t = sym.symbols('t')
> sym.Derivative( (sin(t)+exp(t))**3 , t ).doit()
>
> gives:
> (exp(t) + sin(t))**2*(3*exp(t) + 3*cos(t))
>
> I need the result without any simplifications (in order to detect the
> inner derivative for further calculations)
>
> Should be:
> (exp(t) + sin(t))**2*3*(exp(t) + cos(t))
>
--
You received this message because you are subscribed to the Google Groups
"sympy" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at https://groups.google.com/group/sympy.
To view this discussion on the web visit
https://groups.google.com/d/msgid/sympy/0317a185-3207-413f-885b-cec51d3deb4a%40googlegroups.com.
For more options, visit https://groups.google.com/d/optout.
