Yep.  It's called cse().

Aaron Meurer

On Tuesday, June 7, 2016, Richard Fateman <[email protected]> wrote:

> I think you are merely trying to find common subexpressions to speed up
> evaluation.
> There are lots of ways to do that.
> The simplest is to precompute sin(t), cos(t), exp(t) or whatever
> non-elementary
> functions are involved.  Then you can also consider using horner's rule  or
> something like factor.  But there should be a common-subexpression
> extraction
> program around, no?
> RJF
>
>
> On Tuesday, June 7, 2016 at 11:39:20 AM UTC-7, brombo wrote:
>>
>> You might want to look at "New Foundations for Classical Mechanics" by
>> David Hestenes and the rigid body rotor description of equations of motion.
>>
>>
>> http://www.amazon.com/Foundations-Classical-Mechanics-Fundamental-Theories/dp/0792353021
>>
>> Should be in your school library.
>>
>>
>>
>> On Tue, Jun 7, 2016 at 1:14 PM, Aaron Meurer <[email protected]> wrote:
>>
>>> On Tue, Jun 7, 2016 at 8:58 AM, Michi S <[email protected]> wrote:
>>> >
>>> > Thanks for the answers! For the purpose of my master thesis I am
>>> trying to
>>> > optimize the simulaion of helicopter dynamics. These dynamics are
>>> pretty
>>> > complicated, which leads to huge equations for most states. In order to
>>> > speed up the calculation I need to detect functions that where already
>>> > evaluated. The inner derivative that is produced due to the chain rule
>>> is
>>> > such a function, that I need to detect.
>>> >
>>> > factor() works only for the first derivative unfortunately. In the
>>> second
>>> > and higher derivatives it does not factorize the inner derivates
>>> anymore:
>>> >
>>> > t = sym.symbols('t')
>>> > diff( (sin(t)+exp(t))**5 , t )
>>> >>> (exp(t) + sin(t))**4*(5*exp(t) + 5*cos(t))
>>> >
>>> > factor(diff( (sin(t)+exp(t))**5 , t ))
>>> >>> 5*(exp(t) + sin(t))**4*(exp(t) + cos(t))
>>> >
>>> > factor(diff( (sin(t)+exp(t))**5 , t, t ))
>>> >>> 5*(exp(t) + sin(t))**3*(5*exp(2*t) + 8*exp(t)*cos(t) - sin(t)**2 +
>>> >>> 4*cos(t)**2)
>>>
>>> What output were you expecting here? I don't think the second factor
>>> can be factorized. Note however that it can be simplified slightly if
>>> you call trigsimp() on it.
>>>
>>> Aaron Meurer
>>>
>>> >
>>> >
>>> > I think, writing my own differentiation programm will be a little bit
>>> to
>>> > hard to solve my issue. Is there no other way besides factor() and
>>> wiriting
>>> > my own programm?
>>> >
>>> >
>>> > Thank for your help!
>>> >
>>> >
>>> > Am Mittwoch, 1. Juni 2016 15:34:28 UTC+2 schrieb Michi S:
>>> >>
>>> >> Hello!
>>> >>
>>> >> Is there a way to turn off the automatic simplification by
>>> calculating the
>>> >> derivative of a function? For example
>>> >>
>>> >> t = sym.symbols('t')
>>> >> sym.Derivative( (sin(t)+exp(t))**3 , t ).doit()
>>> >>
>>> >> gives:
>>> >> (exp(t) + sin(t))**2*(3*exp(t) + 3*cos(t))
>>> >>
>>> >> I need the result without any simplifications (in order to detect the
>>> >> inner derivative for further calculations)
>>> >>
>>> >> Should be:
>>> >> (exp(t) + sin(t))**2*3*(exp(t) + cos(t))
>>> >
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