Convert that into lhs - rhs form and try : 

In [39]: eq = Eq(x/y,z).lhs - Eq(x/y, z).rhs


In [40]: eq

Out[40]: 

x    

─ - z

y    



On Friday, 16 December 2016 20:06:36 UTC+5:30, bsdz wrote:
>
> But that doesn't work with Eq. Also how would that work if I wish to do 
> ln(Eq(a*b,c))? Converting the expression to form lhs-rhs wouldn't work.

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