Not quite what I'm asking but thanks anyhow :) On Sunday, 18 December 2016 10:01:07 UTC, Shekhar Prasad Rajak wrote: > > Convert that into lhs - rhs form and try : > > > In [39]: eq = Eq(x/y,z).lhs - Eq(x/y, z).rhs > > > In [40]: eq > > Out[40]: > > x > > ─ - z > > y > > > > On Friday, 16 December 2016 20:06:36 UTC+5:30, bsdz wrote: >> >> But that doesn't work with Eq. Also how would that work if I wish to do >> ln(Eq(a*b,c))? Converting the expression to form lhs-rhs wouldn't work. > >
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