David,

I'm not sure I understand what algebraic manipulations you are referring
to. In the example, the algebraic manipulation is done with sympy
variables. Only the final expressions are evaluated with floating point
numbers substituted in. The substitutions of floating point numbers do have
to occur in the order defined by the underlying tree (or directed acyclic
graph in the case of the cse'd expressions). Those evaluations will have
floating point error accumulation but the magnitude of that error should be
small.

Jason
moorepants.info
+01 530-601-9791


On Fri, Oct 23, 2020 at 10:37 PM David Bailey <d...@dbailey.co.uk> wrote:

> On 23/10/2020 11:59, Oscar Benjamin wrote:
>
> Hi Jason,
>
> I'm approaching this from the perspective that this is a bug in
> cse/lambdify and that you want to identify which part of a large
> expression tree triggers the bug. Since evaluating the whole
> expression is slow I would start by testing smaller subexpressions and
> work up from there. You can get something like that with:
>
> from sympy.utilities.iterables import postorder_traversal
>
> def cse_compare(expr, syms, vals):
>     result = lambdify(syms, expr)(*vals)
>
>     syms_all, vals_all = list(syms), list(vals)
>     reps, [reduced_expr] = cse(expr)
>     for csesym, cseexpr in reps:
>         val = lambdify(syms_all, cseexpr)(*vals_all)
>         syms_all.append(csesym)
>         vals_all.append(val)
>     result_cse = lambdify(syms_all, reduced_expr)(*vals_all)
>
>     return abs(result - result_cse) / abs(result)
>
> def cse_compare_bottom_up(expr):
>     syms = list(expr.free_symbols)
>     vals = list(np.random.random(len(syms)))
>
>     def subexprs():
>         seen = set()
>         for e in postorder_traversal(expr):
>             if e not in seen:
>                 yield e
>                 seen.add(e)
>
>     # possibly better:
>     #exprs = sorted(set(postorder_traversal(expr)), key=lambda e: 
> e.count_ops())
>     exprs = subexprs()
>
>     for subexpr in exprs:
>         print()
>         print(subexpr)
>         print(cse_compare(expr, syms, vals))
>
> test_expr = (sin(x+1) + 2*cos(x-3)).expand(trig=True)
> cse_compare_bottom_up(test_expr)
>
>
> Oscar
>
> On Fri, 23 Oct 2020 at 07:59, Jason Moore <moorepa...@gmail.com> 
> <moorepa...@gmail.com> wrote:
>
> Oscar,
>
> Yes I can try evaluating in different orders. That's an interesting idea.
>
> I also may be breaking lambdify with too many arguments. I can store the 
> numerical results of each subexpression in a dictionary, then identify the 
> minimal set of variables in each subsequent subexpression, and only lambdify 
> with that very much smaller set of arguments. Maybe that will fix it.
>
> I'll try both.
>
> Jasonmoorepants.info
> +01 530-601-9791
>
>
> On Fri, Oct 23, 2020 at 8:56 AM Oscar Gustafsson <oscar.gustafs...@gmail.com> 
> <oscar.gustafs...@gmail.com> wrote:
>
> Yes, you are right that the email is about a different topic. However, it can 
> be worth noting that evaluating floating-point expressions in different 
> order, which is basically what you do using cse:s, can give different results 
> due to the floating-point quantization/rounding happening at different 
> places. Hence, it is not always obvious to tell if the results are 
> "identical". If you are unlucky, the error propagation can be quite 
> disastrous at times, but you are probably correct in that there is something 
> else that is the primary issue here.
>
> BR Oscar
>
> Den tors 22 okt. 2020 kl 18:57 skrev Jason Moore <moorepa...@gmail.com> 
> <moorepa...@gmail.com>:
>
> As far as I understand the results should match to machine precision.
>
> We are able to match these kinds of models executed on different platforms 
> using different formulation techniques to machine precision (e-14 or more). 
> In fact, we use this to be able to verify that two independent modelers have 
> created the same model.
>
> The fact that my model can't get the same results with two numerical 
> evaluations of sympy code is concerning.
>
> My question in this email though, is how to improve the comparison code so 
> that it doesn't crash for large expressions.
>
> Jasonmoorepants.info
> +01 530-601-9791
>
>
> On Thu, Oct 22, 2020 at 6:49 PM Oscar Gustafsson <oscar.gustafs...@gmail.com> 
> <oscar.gustafs...@gmail.com> wrote:
>
> How much do they differ? I checked the issue and the latest result wasn't 
> that bad, although probably too much to blame floating-point errors. However, 
> if you push the numerical range into e.g. denormalized numbers I guess it can 
> simply be that. Not very likely though. Is it still that type of numerical 
> errors?
>
> BR Oscar
>
> Den tors 22 okt. 2020 09:37Jason Moore <moorepa...@gmail.com> 
> <moorepa...@gmail.com> skrev:
>
> Howdy,
>
> I'm trying to track down a bug in this PR:
> https://github.com/pydy/pydy/pull/122
>
> I have quite large SymPy expressions which I evaluate with floating point 
> numbers. I also cse those expressions and evaluate those with the same 
> floating point numbers. I'm getting discrepancies in the results. I'd like to 
> eliminate the possibility that the cse'd expressions are different from the 
> original expression. I wrote this naive function to make the comparison:
>
> def compare_cse(expr):
>
>     args = list(expr.free_symbols)
>     args.remove(TIME)
>     args += me.find_dynamicsymbols(expr)
>     args = list(sm.ordered(args))
>     vals = list(np.random.random(len(args)))
>
>     eval_expr = sm.lambdify(args, expr)
>     res = eval_expr(*vals)
>
>     replacements, reduced_expr = sm.cse(expr)
>     for repl in replacements:
>         var = repl[0]
>         sub_expr = repl[1]
>         eval_sub_expr = sm.lambdify(args, sub_expr)
>         vals.append(eval_sub_expr(*vals))
>         args.append(var)
>     eval_reduced_expr = sm.lambdify(args, reduced_expr[0])
>     cse_res = eval_reduced_expr(*vals)
>
>     np.testing.assert_allclose(res, cse_res)
>
> This seems to work for small expressions, but for the large expressions run 
> this actually kills my Python interpreter after some minutes.
>
> Is there a better way to write this? I need some way to verify that numerical 
> evaluation of a cse'd expression gives the same result as numerical 
> evaluation of the expression that can actually complete in a reasonable 
> amount of time.
>
> Jasonmoorepants.info
> +01 530-601-9791
>
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> I am a bit puzzled that anyone would perform algebraic manipulations on an
> expression involving floating point numbers. Surely this is asking for
> trouble, I mean the sequence a+b+c need not equal a+c+b if a,b,c are
> floating point numbers. I would have thought it would always be better to
> replace the floating point numbers by variables, perform the operation, and
> then substitute the values back into the expression?
>
> This can easily happen without creating denormals, etc.
>
> David
>
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